10x=4x^2+13

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Solution for 10x=4x^2+13 equation: 



10x=4x^2+13

We move all terms to the left:

10x-(4x^2+13)=0

We get rid of parentheses

-4x^2+10x-13=0

a = -4; b = 10; c = -13;
Δ = b2-4ac
Δ = 102-4·(-4)·(-13)
Δ = -108
Delta is less than zero, so there is no solution for the equation

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